Note that eigenvectors are not unique. Multiplying by any constant, including -1 (which simply changes the sign), gives another valid eigenvector. ... <看更多>
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Note that eigenvectors are not unique. Multiplying by any constant, including -1 (which simply changes the sign), gives another valid eigenvector. ... <看更多>
You have an ill-conditioned eigenvalue problem. Consider a perturbation δA in your matrix A—with double-precision floats this is O(10−16). ... <看更多>